Can Someone with skills help me...

The more games you add, the lower your odds go, which leads to more of this


And I just want to point out that vvryan1 has skills Hooraaaay skills!

Ok I will read it...thanks.

After a 9 team parlay the house edge actually goes down for a 10 team parlay.  By the time you get to a 20 team parlay the house edge could be to 0 or negative.  Plus your one dollar bet might make you a millionaire, you should look into it.

You guys are making this way too hard. I did too at first but its really simple. 6 teams total. 2 possible outcomes for each team. (either + or - the points /over under.. whatever) 2x2x2x2x2x2= 64

After reading the article, I basically found out the same thing I already knew--a 2 team parlay has only 4 possible combinations--one of them will be right.  Then it talked alot about odds and how they always make a profit.  But the example used only a 2 or 3 team parlay where the house will most certainly come out ahead.

But, as you add more teams to the parlay...the win amount goes up...and if you add over 6...it really starts to move.  So as the payouts go up, you have the ability to bet more and more possible parlay combinations (just like when we had 2 or 3, but were taking a loss), with higher payouts...my question is...can all the different parlay combinations be bet using let's say $1...and there be a point where the player would be able to profit...

 You telling me there are 128 different combinations for a 7-team parlay?

On a side note: I checked and...a $1 bet on a 12-team parlay would pay $1800.00...too bad I don't know the point total for every NFL game this week. lol

Holy shit give it up already, fuck.   Congrats, you can guarantee yourself an $1800 winner this weekend by spending a dollar on over 4,000 parlay combos.

Well then ok...but tell me how many possible conbinations it would take to cover all possibilities of a 3 team parlay?

NVM...I finally got it. lol

I was confusing myself so much.  Guess it's not really ever possible guarantee that you get them all right, and at the same time make a profit.

However, this could be used on parlays where you felt really confident about 2 or 3 picks and you wanted to throw in other picks you were not sure about.  Then just pick the same 2 or 3 in the all parlays (and hope you were right) and then use different combinations for the other picks you were not as sure on.  Maybe that would work.  But guess there could always be upsets that would change everything.

  I get it now!   

Yes. It has been explained more then once in this thread.

For any number (X) of games, the total possible combination's is 2 to the power of X.

So for 7 games there are 128 possible combination's.

Dude, give it up already. Unless ALL the dogs come in, YOU ARE NOT GOING TO TURN A PROFIT.

Why would you give him another idea to play with  

If you only parlay all the underdogs one of them has to win, right?

Yeah, but he's talking about covering EVERY possible scenario, no matter who wins (Underdog or Favourite). If all the heavy juice favourites come in, guess what? You're still losing money!

Don't you think Vegas and the online books take these things into consideration when they set parlay odds? For the love of God!

Somebody please tell me I didnt just take 15 minutes of my life to read this thread.

15 minutes? You need to work on your speed reading van.

Tom Cruise made 3 shit movies about this

THE BOOKIES LOVE YOU ROOKIES

@After_I_Win

 Did you find anything out 

throwback thread  

 

 

Someone has thought of money laundering....

 

@Dude15

I am intrigued by After_ I am a degenerate and didn’t know someone else has the same idea I did. It works ! 

@After_I_Win

 Idk if you are alive still bet or use this account but its simple algebra permutations and combinations thier are online website that give you a list

@After_I_Win

 It works 7 team parlay is 128 different combinations of a 7 team parlay and atleast one underdog on the board you will make expected for if it’s of 62$ if you are betting 1$ on each combination

@After_I_Win

 For 5 game parlay there’s 36 combos 1$ each will have a 29$ loss with a 85$ win witch will leave your profits at around the 50$ area the point is to play 5 games that all have a underdog and atleast one team with a hit underdog that you think will hit put those five teams at 1$ each 

 So does anyone know if it is possible to cover all possible outcomes of a 6 team parlay? And how many parlays would it take to have a correct combination in one of them?

Here is the math.

For 110 110

2 teams 2 squared 4. 

This bet loses. Because of the juice.

So 3

2 cubed 2x2x2 one in 8

4 teams 

2x2x2x2 2 to the 4th 1 in 16

2x2x2x2x2 2 to the 5th power 1/32

2x2x2x2x2x2 2 to the 6th 1 /64

Ect.....

If the odds are offset say horses. And a 1/8 wins the first race on a 6 race ticket as example implied odds and actual 50/50 greatly exaggerated to add value in bets....