Is a $1500 bankroll good enough to wanna bet to win $50 just on the rotation play? If not what should I have or what should I be betting having a $1500 bankroll? Thanks Hat!
no, you will not be able to got past game 3 with that. It has already gone to Game 4 once this year.
$1500 BR for a 5 game system with -166 average odds will limit you to a $10 unit size.
Or you could play games C, D & E only with $50 units, but you will lose out on the wins.
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Quote Originally Posted by L-Rod:
Is a $1500 bankroll good enough to wanna bet to win $50 just on the rotation play? If not what should I have or what should I be betting having a $1500 bankroll? Thanks Hat!
no, you will not be able to got past game 3 with that. It has already gone to Game 4 once this year.
$1500 BR for a 5 game system with -166 average odds will limit you to a $10 unit size.
Or you could play games C, D & E only with $50 units, but you will lose out on the wins.
Here is the breakdown of your what your units should be per bet with odds factored in.....
First determine what is the MOST you want to Bet if you lost on ALL of the 4 game plus average -150 odds. Lets say 1000.00$
The algorithm would look like this.......
a = first bet
2.5a =second bet
6.25a = third bet
16a = fourth bet
Take your max amount you want to lose on a 4 game series chase and divide by 16. Lets say 1000.00$.......... 1000.00% divided by 16= 62.50$ that would be your first bet
bet a would then be....62.50 $>>>>>
if lost at -150 odds = 93.75$ lost bet a
bet b....2.5 x 62.50$= 156.25$>>>> this covers what you lost in a bet and adds 1 unit profit (93.75 + 62.50)
if lose b bet at -150 avg odds =234.37 lost b bet
bet c....6.25 x 62.50= 390.62>>>> this covers what you lost in a bet and b bet plus adds 1 unit profit (93.75 +234.37 + 62.50)
if lose c bet at -150 avg odds =585.93 lost bet
bet d.... 16 x 62.50= 1000.00 this covers what you lost in a bet, b bet, c bet, plus adds 1 unit profit (93.75 + 234.37 +585.93 + 62.50)
If d bet loses you will lose 1000.00 at -150 odds a total of 1500$
if you dont want to risk more than 5% of your roll on any one (D)bet, you would need a starting roll of 30,000$ to support a 1,500 loss with an (A) bet of only 62.50$
I hope this helps
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You guys are driving me crazy
Here is the breakdown of your what your units should be per bet with odds factored in.....
First determine what is the MOST you want to Bet if you lost on ALL of the 4 game plus average -150 odds. Lets say 1000.00$
The algorithm would look like this.......
a = first bet
2.5a =second bet
6.25a = third bet
16a = fourth bet
Take your max amount you want to lose on a 4 game series chase and divide by 16. Lets say 1000.00$.......... 1000.00% divided by 16= 62.50$ that would be your first bet
bet a would then be....62.50 $>>>>>
if lost at -150 odds = 93.75$ lost bet a
bet b....2.5 x 62.50$= 156.25$>>>> this covers what you lost in a bet and adds 1 unit profit (93.75 + 62.50)
if lose b bet at -150 avg odds =234.37 lost b bet
bet c....6.25 x 62.50= 390.62>>>> this covers what you lost in a bet and b bet plus adds 1 unit profit (93.75 +234.37 + 62.50)
if lose c bet at -150 avg odds =585.93 lost bet
bet d.... 16 x 62.50= 1000.00 this covers what you lost in a bet, b bet, c bet, plus adds 1 unit profit (93.75 + 234.37 +585.93 + 62.50)
If d bet loses you will lose 1000.00 at -150 odds a total of 1500$
if you dont want to risk more than 5% of your roll on any one (D)bet, you would need a starting roll of 30,000$ to support a 1,500 loss with an (A) bet of only 62.50$
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