okay I stand corrected the first number can be 1 but it cant be over 65 like wise second number can be 2 but not over 66 ect.so the number is 65 times 64 times 63 times 62 times 61 times 26 powerball numbers the exact combinations are 27,917,287,424
around 28 billion to one.
You need more correction. The odds you worked out are for picking the balls in the correct order. You need to divide by 5 * 4 * 3 * 2 which are the number of ways 5 numbers can be ordered which will give you the 292.2 million.
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Quote Originally Posted by nature1970:
okay I stand corrected the first number can be 1 but it cant be over 65 like wise second number can be 2 but not over 66 ect.so the number is 65 times 64 times 63 times 62 times 61 times 26 powerball numbers the exact combinations are 27,917,287,424
around 28 billion to one.
You need more correction. The odds you worked out are for picking the balls in the correct order. You need to divide by 5 * 4 * 3 * 2 which are the number of ways 5 numbers can be ordered which will give you the 292.2 million.
You need more correction. The odds you worked out are for picking the balls in the correct order. You need to divide by 5 * 4 * 3 * 2 which are the number of ways 5 numbers can be ordered which will give you the 292.2 million.
no I took that into consideration showing the balls fall from the cage
69 balls one leaves then 68 one leaves then 67 one leaves then 66 one leaves finally 65 remaining one leaves leaving 64 balls in the cage.
then it became confused by perceived chance of the balls falling 12345 1 I argue any combination had a valid chance as any other. so I stated 35 billion to one but then actual results were dictated to factor what is reality of the first number greater than 50. ect ect.
so then I was working with the actual odds implied by the back of the ticket to come up with the 33 raised to 5 times 26 as the only way a 292 million to one chance to exist.
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Quote Originally Posted by thorpe:
You need more correction. The odds you worked out are for picking the balls in the correct order. You need to divide by 5 * 4 * 3 * 2 which are the number of ways 5 numbers can be ordered which will give you the 292.2 million.
no I took that into consideration showing the balls fall from the cage
69 balls one leaves then 68 one leaves then 67 one leaves then 66 one leaves finally 65 remaining one leaves leaving 64 balls in the cage.
then it became confused by perceived chance of the balls falling 12345 1 I argue any combination had a valid chance as any other. so I stated 35 billion to one but then actual results were dictated to factor what is reality of the first number greater than 50. ect ect.
so then I was working with the actual odds implied by the back of the ticket to come up with the 33 raised to 5 times 26 as the only way a 292 million to one chance to exist.
i do understand why 69 balls fall 69/5 *68/4 *67/3 *66/2*65*26
could be used to A ticket has one in 292 million chance but to cover EVERY combination in a spread would be 69*68*67*66*65*26 35 billion possibilities.
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Quote Originally Posted by Nflmaestro:
nature your math is incorrect
good day
i do understand why 69 balls fall 69/5 *68/4 *67/3 *66/2*65*26
could be used to A ticket has one in 292 million chance but to cover EVERY combination in a spread would be 69*68*67*66*65*26 35 billion possibilities.
in the micro 292 million to one if you bought 292 million tickets you be the winner but that is not true.
say you bought two tickets what would the odds be under the odds of micro you could determine you gained one. but you dont you only gain less than .001 but i would like to see the math that shows a hedgefund could purchase all the numbers for under 600 million.
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in the micro 292 million to one if you bought 292 million tickets you be the winner but that is not true.
say you bought two tickets what would the odds be under the odds of micro you could determine you gained one. but you dont you only gain less than .001 but i would like to see the math that shows a hedgefund could purchase all the numbers for under 600 million.
Lets say you have 100 Million cash in your bank account.
Would you call the Lotto officials and say you want to buy every number combination possible. If my numbers are right with a 1 in 292.2 million of getting the right number combination it would take 584.4 million to buy every combination. I would also assume that a portion of that goes into the pot climbing the total well over 1B.
The big question...(if you had that money of course)... Would you take the chance on buying every number combination...
If you say yes...would you try to pick 1 number that wouldn't hit and skip every ticket that included that number.... how far would you go with leaving numbers off so you decrease the amount spent.....
this is the formula for A ticket odds 69 balls one falls you have 5 ect ect chances 69*5*68*4*67*3*66*2*65*26=292 million.
the macro is 69*68*67*66*65*26= 35 billion combinations.
The point the micro and the macro would meet sweet spot as you will would be 13.8 tickets and every power ball per ticket so we round up 14 tickets with 5 all most independent numbers per ticket two tickets would have a single number in common to handicap the chance of winning it all to 1 in 814,384 with a guaranteed payout of at least 70.00 for an investment of 728 and if you could build a ticket to win powerball after that point in this parabola odds creation anymore money would only decrease the odds by fractions of one percent.
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Quote Originally Posted by BigGame90:
Lets say you have 100 Million cash in your bank account.
Would you call the Lotto officials and say you want to buy every number combination possible. If my numbers are right with a 1 in 292.2 million of getting the right number combination it would take 584.4 million to buy every combination. I would also assume that a portion of that goes into the pot climbing the total well over 1B.
The big question...(if you had that money of course)... Would you take the chance on buying every number combination...
If you say yes...would you try to pick 1 number that wouldn't hit and skip every ticket that included that number.... how far would you go with leaving numbers off so you decrease the amount spent.....
this is the formula for A ticket odds 69 balls one falls you have 5 ect ect chances 69*5*68*4*67*3*66*2*65*26=292 million.
the macro is 69*68*67*66*65*26= 35 billion combinations.
The point the micro and the macro would meet sweet spot as you will would be 13.8 tickets and every power ball per ticket so we round up 14 tickets with 5 all most independent numbers per ticket two tickets would have a single number in common to handicap the chance of winning it all to 1 in 814,384 with a guaranteed payout of at least 70.00 for an investment of 728 and if you could build a ticket to win powerball after that point in this parabola odds creation anymore money would only decrease the odds by fractions of one percent.
14 sets of tickets each set five different numbers spare two tickets would have a number in common and every set of numbers has 26 power ball numbers for a total of 364 tickets in the lot. would bring the chance to win this under 1 in a million.
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14 sets of tickets each set five different numbers spare two tickets would have a number in common and every set of numbers has 26 power ball numbers for a total of 364 tickets in the lot. would bring the chance to win this under 1 in a million.
So lets say the numbers are right and there is 292.2 million combinations to secure every possible draw. Each ticket costs $2 292.2 X 2= 584.4million to secure every combination.
Now if you had the 1 Billion would you risk almost half your money for the chance to be the sole winner of 1.5 Billion?
After taxes with a lump sum you could be looking at 800million.
So essentially you're playing 584 million to win close to 250 million possibly more (quick guess on the final pay out. All likelihood the pot gets bigger by Wednesday).
Since they added extra numbers the odds of hitting have increased so there is still a chance nobody hits this next drawing.
If you had the money (but not excessively more where a loss would hurt but not cripple you) would you make the play against everyone else assuming after taxes you make a profit if nobody else hits?
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So lets say the numbers are right and there is 292.2 million combinations to secure every possible draw. Each ticket costs $2 292.2 X 2= 584.4million to secure every combination.
Now if you had the 1 Billion would you risk almost half your money for the chance to be the sole winner of 1.5 Billion?
After taxes with a lump sum you could be looking at 800million.
So essentially you're playing 584 million to win close to 250 million possibly more (quick guess on the final pay out. All likelihood the pot gets bigger by Wednesday).
Since they added extra numbers the odds of hitting have increased so there is still a chance nobody hits this next drawing.
If you had the money (but not excessively more where a loss would hurt but not cripple you) would you make the play against everyone else assuming after taxes you make a profit if nobody else hits?
i do understand why 69 balls fall 69/5 *68/4 *67/3 *66/2*65*26
could be used to A ticket has one in 292 million chance but to cover EVERY combination in a spread would be 69*68*67*66*65*26 35 billion possibilities.
Obviously this is incorrect. Above link touches on it. 1/292 M. Very simple. Problem is you can't buy that many tickets in time and may have to split the winnings.
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Quote Originally Posted by nature1970:
i do understand why 69 balls fall 69/5 *68/4 *67/3 *66/2*65*26
could be used to A ticket has one in 292 million chance but to cover EVERY combination in a spread would be 69*68*67*66*65*26 35 billion possibilities.
Obviously this is incorrect. Above link touches on it. 1/292 M. Very simple. Problem is you can't buy that many tickets in time and may have to split the winnings.
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Problem is you can't buy that many tickets in time and may have to split the winnings. 
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