Today's Over/Under is Winnipeg-Montreal Over 5,5 with odds 2,25 (+125). 10 dollars to win 22,5 dollars.
Lets do some calculations with this system:
1. Assumption:
- All games are pretty much a coin flip on whether they will be Over or Under. Hence betting the one with the highest odds brings profits in the long run.
2. Calculating the profits.
- We bet 10 dollars per game with average odds of 2,25 (+125)
- We win every second game, hence we make a 2,5 dollar profit every two games, thats ca 1,25 dollars per day (if there is one game to play per day).
- If there are two games per day, we make 2,5 dollars per day with the method shown above. We will also make an additional 5 dollars profit for every 4 doubles we play. That is because we hit it 1 time out of 4. 20 dollars brings ca 25 dollars each time.
3. Overall profit from all that above:
- 1 game per day: 1,25 dollars per day
- 2 games per day: 3,75 dollar per day
So we should really strive for having 2 games per day. We will get that too as normally there will be games with Over/Under of 5,5 and 4,5. We pick the highest odds from each.
What if the system works and we would play ALL odds of 2,20 or more?
- Lets calculate:
-> eg ca 4 matches per day (theres probably more like 6): makes 5 dollars per day. Not sure if we would do any doubles or bigger parlays then. Would have to calculate the benefits.
What if we only did Doubles?
- e.g. 1 double per day. 10 dollars to win 50. We win it 1 time out of 4. Daily profit is 2,5 dollars.
To me it sounds like the best bet would be to have 2 games per day, make 2 singles out of them and a double.
I am though interested in playing all games on a given day.
ROI on this system would be:
- 1 game per day (or 2 games or 3 or 4 if its all singles): 12,5 %
- 2 games per day + a double: 15 %
Dont feel like calculating the bigger parlays right now. If this seems to work might as well do them as well.
But how about a negative/positive progressive systems? We need to calculate those!
1. Simplified: 1 game per day (betting 1,2,5 units). Unit is 10 dollars.
- We win first, we are up 1,2 units, thats 12 dollars, 12 dollars per day.
- We lose the first, win second, we are up 1,4 units, so 14 dollars, we have 7 dollars per day.
- We lose the first, lose second, win third, up 3 units, so 30 dollars, thats 10 dollars per day
- We lose all 3, we lose 8 units, thats 80 dollars.
How many times would we lose 3 in a row? Lets say we win 1 on first, 1 on 2nd and 1 on 3rd and then lose 3 in a row. We would win 56 dollars and lose 80. If we dont lose 3 in a row every 4th time, but lets say every 7th time, we would win 112 and lose 80. Profit of 32, Divide that profit with the amount of days 1+2+3+1+2+3+3=15. 32/15 is 2,13 dollars per day.
If I calculated that right... I dont think its worth it, Just increases the variance and doesnt sound like it brings that much extra profit, if at all, especially compared to the hope 2 games per day + a double. The system above is still more proftable than just 1 single per day, but the difference in variance is pretty huge.
Ok, too much maths. Please correct me if you see any blatant mistakes. I dont feel like calculating a positive progressive system either at least yet.
Lets see how this goes, feels good at least now
By the way, we have not decided what to do if there are e.g. 6 games with the same 2,2 odds.. We will probably play them all in that case.